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Disabled 'is_palindrome' for 'const char*'
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@ -79,6 +79,8 @@ All of the variants of `is_palindrome` take their parameters by value or const r
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* If you use version of 'is_palindrome' without custom predicate, 'is_palindrome' uses default 'operator==' for elements. If you want use custom predicate, you must redefine 'operator=='.
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* If you use version of 'is_palindrome' without custom predicate, 'is_palindrome' uses default 'operator==' for elements. If you want use custom predicate, you must redefine 'operator=='.
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* Don't use 'const char*' with 'is_palindrome', because 'const char*' is always non-palindromic ('\0' at the end). If you will try to compile 'is_palindrome' with 'const char*', you will get an error.
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[endsect]
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[endsect]
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[/ File is_palindrome.qbk
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[/ File is_palindrome.qbk
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@ -102,6 +102,22 @@ bool is_palindrome(const R& range, Predicate p)
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return is_palindrome(boost::begin(range), boost::end(range), p);
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return is_palindrome(boost::begin(range), boost::end(range), p);
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}
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}
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//Disable is_palindrome for const char* because it work not properly.
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//Please use string_view for const char* cases.
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//Here we use dirty hack to disable 'is_palindrome' with 'const char*'
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//URL: http://stackoverflow.com/questions/14637356/static-assert-fails-compilation-even-though-template-function-is-called-nowhere
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template<typename T>
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struct foobar : std::false_type
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{ };
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template<typename T = int>
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bool is_palindrome(const char* str)
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{
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static_assert(foobar<T>::value, "Using 'is_palindrome' for 'const char*' is dangerous, because result is always false"
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"(reason: '\0' in the end of the string). You can use string_view in this case");
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return false;
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}
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}}
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}}
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#endif // BOOST_ALGORITHM_IS_PALINDROME_HPP
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#endif // BOOST_ALGORITHM_IS_PALINDROME_HPP
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