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the locale a member, but that would make the example longer. Also, this would be a good place to put a note about the need for constant function objects. [SVN r41995]
80 lines
2.3 KiB
C++
80 lines
2.3 KiB
C++
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// Copyright 2006-2007 Daniel James.
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// Distributed under the Boost Software License, Version 1.0. (See accompanying
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// file LICENSE_1_0.txt or copy at http://www.boost.org/LICENSE_1_0.txt)
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#include <boost/unordered_map.hpp>
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#include <boost/detail/lightweight_test.hpp>
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#include <boost/algorithm/string/predicate.hpp>
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//[case_insensitive_functions
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struct iequal_to
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: std::binary_function<std::string, std::string, bool>
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{
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bool operator()(std::string const& x,
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std::string const& y) const
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{
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return boost::algorithm::iequals(x, y, std::locale());
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}
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};
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struct ihash
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: std::unary_function<std::string, std::size_t>
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{
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std::size_t operator()(std::string const& x) const
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{
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std::size_t seed = 0;
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std::locale locale;
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for(std::string::const_iterator it = x.begin();
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it != x.end(); ++it)
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{
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boost::hash_combine(seed, std::toupper(*it, locale));
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}
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return seed;
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}
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};
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struct word_info;
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//]
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struct word_info {
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int tag;
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explicit word_info(int t = 0) : tag(t) {}
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};
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int main() {
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//[case_insensitive_dictionary
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boost::unordered_map<std::string, word_info, ihash, iequal_to>
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idictionary;
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//]
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BOOST_TEST(idictionary.empty());
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idictionary["one"] = word_info(1);
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BOOST_TEST(idictionary.size() == 1);
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BOOST_TEST(idictionary.find("ONE") != idictionary.end() &&
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idictionary.find("ONE") == idictionary.find("one"));
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idictionary.insert(std::make_pair("ONE", word_info(2)));
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BOOST_TEST(idictionary.size() == 1);
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BOOST_TEST(idictionary.find("ONE") != idictionary.end() &&
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idictionary.find("ONE")->first == "one" &&
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idictionary.find("ONE")->second.tag == 1);
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idictionary["One"] = word_info(3);
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BOOST_TEST(idictionary.size() == 1);
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BOOST_TEST(idictionary.find("ONE") != idictionary.end() &&
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idictionary.find("ONE")->first == "one" &&
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idictionary.find("ONE")->second.tag == 3);
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idictionary["two"] = word_info(4);
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BOOST_TEST(idictionary.size() == 2);
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BOOST_TEST(idictionary.find("two") != idictionary.end() &&
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idictionary.find("TWO")->first == "two" &&
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idictionary.find("Two")->second.tag == 4);
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return boost::report_errors();
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}
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