find_{not,*backward} docs copy editing.

doc/find_backward.qbk

@@ -11,7 +11,7 @@ Distributed under the Boost Software License, Version 1.0.
 
 The header file 'find_backward.hpp' contains variants of the stl algorithm
 `find`. These variants are like `find`, except that the evaluate the elements
-of the given sequence if reverse order.
+of the given sequence in reverse order.
 
 Consider how finding the last element that is equal to `x` in a range is
 typically done:
@@ -23,7 +23,7 @@ typically done:
         }
     }
 
-Raw loops are icky though.  PErhaps we should do a bit of extra work to allow
+Raw loops are icky though.  Perhaps we should do a bit of extra work to allow
 the use of `std::find()`:
 
     auto rfirst = std::make_reverse_iterator(last);
@@ -31,31 +31,31 @@ the use of `std::find()`:
     auto it = std::find(rfirst, rlast);
     // Use it here...
 
-That seems nicer, but it has two major drawbacks.  First, it requires an
-unpleasant amount of typing.  Second, it is considerably less efficient than
-forward-iterator `find` , since `std::reverse_iterator` calls its
-base-iterator's `operator--()` in most of its members before doing the work
-that the member requires.
+That seems nicer in that there is no raw loop, but it has two major drawbacks.
+First, it requires an unpleasant amount of typing.  Second, it is less
+efficient than forward-iterator `find` , since `std::reverse_iterator` calls
+its base-iterator's `operator--()` in most of its member functions before
+doing the work that the member function requires.
 
 [heading interface]
 
     template<typename BidiIter, typename T>
-    BidiIter find_backward(BidiIter first, BidiIter last, T const & x);
+    BidiIter find_backward(BidiIter first, BidiIter last, const T & x);
 
     template<typename Range, typename T>
-    boost::range_iterator<Range> find_backward(Range & range, T const & x);
+    boost::range_iterator<Range> find_backward(Range & range, const T & x);
 
-The function `find_backward` returns an iterator to the last element that is
-equal to `x` in `[first, last)` or `r`, respectively.
+These overloads of `find_backward` return an iterator to the last element that
+is equal to `x` in `[first, last)` or `r`, respectively.
 
     template<typename BidiIter, typename T>
-    BidiIter find_not_backward(BidiIter first, BidiIter last, T const & x);
+    BidiIter find_not_backward(BidiIter first, BidiIter last, const T & x);
 
     template<typename Range, typename T>
-    boost::range_iterator<Range> find_not_backward(Range & range, T const & x);
+    boost::range_iterator<Range> find_not_backward(Range & range, const T & x);
 
-The function `find_not_backward` returns an iterator to the last element that
-is not equal to `x` in `[first, last)` or `r`, respectively.
+These overloads of `find_not_backward` return an iterator to the last element
+that is not equal to `x` in `[first, last)` or `r`, respectively.
 
     template<typename BidiIter, typename Pred>
     BidiIter find_if_backward(BidiIter first, BidiIter last, Pred p);
@@ -63,8 +63,8 @@ is not equal to `x` in `[first, last)` or `r`, respectively.
     template<typename Range, typename Pred>
     boost::range_iterator<Range> find_if_backward(Range & range, Pred p);
 
-The function `find_if_backward` returns an iterator to the last element for
-which `pred` returns `true` in `[first, last)` or `r`, respectively.
+These overloads of `find_if_backward` return an iterator to the last element
+for which `pred` returns `true` in `[first, last)` or `r`, respectively.
 
     template<typename BidiIter, typename Pred>
     BidiIter find_if_not_backward(BidiIter first, BidiIter last, Pred p);
@@ -72,8 +72,9 @@ which `pred` returns `true` in `[first, last)` or `r`, respectively.
     template<typename Range, typename Pred>
     boost::range_iterator<Range> find_if_not_backward(Range & range, Pred p);
 
-The function `find_if_not_backward` returns an iterator to the last element
-for which `pred` returns `false` in `[first, last)` or `r`, respectively.
+These overloads of `find_if_not_backward` return an iterator to the last
+element for which `pred` returns `false` in `[first, last)` or `r`,
+respectively.
 
 [heading Examples]
 

doc/find_not.qbk

@@ -23,9 +23,7 @@ the first occurrance of any number besides `1` in `vec`?  We have to write an
 unfortunate amount of code:
 
     auto std::vector<int> vec = { 1, 1, 2 };
-    auto it = std::find_if(
-        vec.begin(), vec.end(),
-        [](int i) { return i != 1; });
+    auto it = std::find_if(vec.begin(), vec.end(), [](int i) { return i != 1; });
 
 With `find_not()` the code gets much more terse:
 
@@ -35,18 +33,18 @@ With `find_not()` the code gets much more terse:
 The existing `find` variants are: `find()`, `find_if()`, and `find_if_not()`.
 It seems natural to also have `find_not()`, for the very reason that we have
 `find_if_not()` -- to avoid having to write a lambda to wrap the negation of
-our find condition.
+the find condition.
 
 [heading interface]
 
     template<typename InputIter, typename Sentinel, typename T>        
-    InputIter find_not(InputIter first, Sentinel last, T const & x);
+    InputIter find_not(InputIter first, Sentinel last, const T & x);
 
     template<typename Range, typename T>
-    boost::range_iterator<Range> find_not(Range & r, T const & x);
+    boost::range_iterator<Range> find_not(Range & r, const T & x);
 
-The function `find_not` returns the first value that is not equal to `x` in
-the sequence `[first, last)` or `r`, respectively.
+These overloads of `find_not` return the first value that is not equal to `x`
+in the sequence `[first, last)` or `r`, respectively.
 
 [heading Examples]
 
@@ -57,7 +55,7 @@ Given the container `c1` containing `{ 0, 1, 2 }`,  then
 
 [heading Iterator Requirements]
 
-`equal` works on all iterators except output iterators.
+`find_not` works on all iterators except output iterators.
 
 The template parameter `Sentinel` is allowed to be different from `InputIter`,
 or they may be the same.  For an `InputIter` `it` and a `Sentinel` `end`, `it