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boost_algorithm/doc/find_backward.qbk
2018-05-12 16:04:12 -05:00

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[/ File find_backward.qbk]
[section:find_backward find_backward ]
[/license
Copyright (c) 2018 T. Zachary Laine
Distributed under the Boost Software License, Version 1.0.
(See accompanying file LICENSE_1_0.txt or copy at http://www.boost.org/LICENSE_1_0.txt)
]
The header file 'find_backward.hpp' contains variants of the stl algorithm
`find`. These variants are like `find`, except that the evaluate the elements
of the given sequence if reverse order.
Consider how finding the last element that is equal to `x` in a range is
typically done:
// Assume a valid range if elements delimited by [first, last).
while (last-- != first) {
if (*last == x) {
// Use last here...
}
}
Raw loops are icky though. PErhaps we should do a bit of extra work to allow
the use of `std::find()`:
auto rfirst = std::make_reverse_iterator(last);
auto rlast = std::make_reverse_iterator(first);
auto it = std::find(rfirst, rlast);
// Use it here...
That seems nicer, but it has two major drawbacks. First, it requires an
unpleasant amount of typing. Second, it is considerably less efficient than
forward-iterator `find` , since `std::reverse_iterator` calls its
base-iterator's `operator--()` in most of its members before doing the work
that the member requires.
[heading interface]
template<typename BidiIter, typename T>
BidiIter find_backward(BidiIter first, BidiIter last, T const & x);
template<typename Range, typename T>
boost::range_iterator<Range> find_backward(Range & range, T const & x);
The function `find_backward` returns an iterator to the last element that is
equal to `x` in `[first, last)` or `r`, respectively.
template<typename BidiIter, typename T>
BidiIter find_not_backward(BidiIter first, BidiIter last, T const & x);
template<typename Range, typename T>
boost::range_iterator<Range> find_not_backward(Range & range, T const & x);
The function `find_not_backward` returns an iterator to the last element that
is not equal to `x` in `[first, last)` or `r`, respectively.
template<typename BidiIter, typename Pred>
BidiIter find_if_backward(BidiIter first, BidiIter last, Pred p);
template<typename Range, typename Pred>
boost::range_iterator<Range> find_if_backward(Range & range, Pred p);
The function `find_if_backward` returns an iterator to the last element for
which `pred` returns `true` in `[first, last)` or `r`, respectively.
template<typename BidiIter, typename Pred>
BidiIter find_if_not_backward(BidiIter first, BidiIter last, Pred p);
template<typename Range, typename Pred>
boost::range_iterator<Range> find_if_not_backward(Range & range, Pred p);
The function `find_if_not_backward` returns an iterator to the last element
for which `pred` returns `false` in `[first, last)` or `r`, respectively.
[heading Examples]
Given the container `c1` containing `{ 2, 1, 2 }`, then
find_backward ( c1.begin(), c1.end(), 2 ) --> --c1.end()
find_backward ( c1.begin(), c1.end(), 3 ) --> c1.end()
find_if_backward ( c1.begin(), c1.end(), [](int i) {return i == 2;} ) --> --c1.end()
find_if_backward ( c1.begin(), c1.end(), [](int i) {return i == 3;} ) --> c1.end()
find_not_backward ( c1.begin(), c1.end(), 2 ) --> std::prev(c1.end(), 2)
find_not_backward ( c1.begin(), c1.end(), 1 ) --> c1.end()
find_if_not_backward ( c1.begin(), c1.end(), [](int i) {return i == 2;} ) --> std::prev(c1.end(), 2)
find_if_not_backward ( c1.begin(), c1.end(), [](int i) {return i == 1;} ) --> c1.end()
[heading Iterator Requirements]
All variants work on bidirectional iterators.
[heading Complexity]
Linear.
[heading Exception Safety]
All of the variants take their parameters by value and do not depend upon any
global state. Therefore, all the routines in this file provide the strong
exception guarantee.
[heading Notes]
All variants are `constexpr` in C++14 or later.
[endsect]
[/ File equal.qbk
Copyright 2018 T. Zachary Laine
Distributed under the Boost Software License, Version 1.0.
(See accompanying file LICENSE_1_0.txt or copy at http://www.boost.org/LICENSE_1_0.txt).
]