feedc0de/boost_conversion
1
0
Fork 0
forked from boostorg/conversion
Code Pull Requests Activity

Replace .c_str() with .data() in documentation (refs #6663)

Browse Source 
[SVN r80377]
This commit is contained in:
Antony Polukhin
2012-09-03 17:23:16 +00:00
parent c290a26625
commit c43b86d7f1
1 changed files with 2 additions and 2 deletions
Download Patch File Download Diff File Expand all files Collapse all files

4
doc/lexical_cast.qbk
View File

@@ -83,7 +83,7 @@ Following example takes part of the string and converts it to `int`:
``
int convert_strings_part(const std::string& s, std::size_t pos, std::size_t n)
{
return boost::lexical_cast<int>(s.c_str() + pos, n);
return boost::lexical_cast<int>(s.data() + pos, n);
}
``
[endsect]
@@ -267,7 +267,7 @@ limitation of compiler options that you use.
]
* [*Question:] What is the fastest way to convert a non zero terminated string or a substring using `boost::lexical_cast`?
* [*Answer:] Use `boost::iterator_range` for conversion or `lexical_cast` overload with two parameters. For example, if you whant to convert to `int` two characters from a string `str`, you shall write `lexical_cast<int>(make_iterator_range(str.c_str(), str.c_str() + 2));` or `lexical_cast<int>(str.c_str(), 2);`.
* [*Answer:] Use `boost::iterator_range` for conversion or `lexical_cast` overload with two parameters. For example, if you whant to convert to `int` two characters from a string `str`, you shall write `lexical_cast<int>(make_iterator_range(str.data(), str.data() + 2));` or `lexical_cast<int>(str.data(), 2);`.
[endsect]