feedc0de/boost_range
1
0
Fork 0
forked from boostorg/range
Code Pull Requests Activity

[range] merge doc fixes (r81888, r81889) from trunk

Browse Source 
[SVN r82138]
This commit is contained in:
Nathan Ridge
2012-12-21 08:44:32 +00:00
parent bda0d613c1
commit a417560f09
165 changed files with 2312 additions and 2240 deletions
Download Patch File Download Diff File Expand all files Collapse all files

2
doc/reference/algorithm/fill_n.qbk
View File

@ -14,7 +14,7 @@ ForwardRange& fill( ForwardRange& rng, Size n, const Value& val );
[heading Description]
`fill_n` assigns the value `val` to `n` elements in the range `rng` begining with `boost::begin(rng)`.
`fill_n` assigns the value `val` to `n` elements in the range `rng` beginning with `boost::begin(rng)`.
[heading Definition]

2
doc/reference/algorithm/lexicographical_compare.qbk
View File

@ -41,7 +41,7 @@ Defined in the header file `boost/range/algorithm/lexicographical_compare.hpp`
* `SinglePassRange2` is a model of the __single_pass_range__ Concept.
* `SinglePassRange1`'s value type is a model of the `LessThanComparableConcept`.
* `SinglePassRange2`'s value type is a model of the `LessThanComparableConcept`.
* Let `x` be an object of `SinglePassRange1`'s value type. Let `y` be an obect of `SinglePassRange2`'s value type. `x < y` must be valid. `y < x` must be valid.
* Let `x` be an object of `SinglePassRange1`'s value type. Let `y` be an object of `SinglePassRange2`'s value type. `x < y` must be valid. `y < x` must be valid.
[*For the predicate versions of lexicographical_compare:]

2
doc/reference/algorithm/mismatch.qbk
View File

@ -80,7 +80,7 @@ mismatch(const SinglePassRange1& rng1, SinglePassRange2& rng2,
[heading Description]
`mismatch` finds the first position where the correseponding elements from the two ranges `rng1` and `rng2` are not equal.
`mismatch` finds the first position where the corresponding elements from the two ranges `rng1` and `rng2` are not equal.
Equality is determined by `operator==` for non-predicate versions of `mismatch`, and by satisfying `pred` in the predicate versions.