Boost.Utility/IdentityType 1.0.0

Lorenzo Caminiti

Distributed under the Boost Software License, Version 1.0 (see accompanying file LICENSE_1_0.txt or a copy at http://www.boost.org/LICENSE_1_0.txt)

Table of Contents

Motivation
Solution
Templates
Abstract Types
Compilers and Platforms
Annex: Usage
Annex: Implementation
Reference

This library allows to wrap type expressions within round parenthesis so they can be passed to macros even when they contain commas.

Consider the following macro which declares a variable named varn with the specified type (see also var_error.cpp):

#define VAR(type, n) type var ## n

VAR(int, 1);                    // OK.
VAR(std::map<int, char>, 2);    // Error.

The first macro invocation works correctly declaring a variable named var1 of type int. However, the second macro invocation fails generating a preprocessor error similar to the following:

error: macro "VAR" passed 3 arguments, but takes just 2

That is because the std::map type passed as the first macro parameter contains a comma , not wrapped by round parenthesis (). The preprocessor interprets that unwrapped comma as a separation between macro parameters concluding that a total of three (and not two) parameters are passed to the macro in the following order:

  1. std::map<int
  2. char>
  3. 2

Note that, differently from the compiler, the preprocessor only recognizes round parameters (). Angular <> or squared [] parenthesis are not used by the preprocessor when parsing the macro parameters.

In some cases, it might be possible to workaround this issue by avoiding to pass the type expression to the macro all together. For example, in some cases a typedef can be used to specify the type expression with the commas outside the macro (see also var.cpp):

typedef std::map<int, char> map_type;
VAR(map_type, 3); // OK.

When this is not possible or desired (e.g., see the function template f in the section below), the library header boost/utility/identity_type.hpp defines a macro BOOST_IDENTITY_TYPE which can be used to workaround the issue while keeping the type expression as one of the macro parameters (see also var.cpp).

#include <boost/utility/identity_type.hpp>

VAR(BOOST_IDENTITY_TYPE((std::map<int, char>)), 4); // OK.

This macro expands to an expression that evaluates (at compile-time) to the specified type. The specified type is never split into multiple macro parameters because it is always wrapped by a set of extra round parenthesis (). In fact, a total of two sets of round parenthesis must be used: The parenthesis to invoke the macro BOOST_IDENTITY_TYPE(...) plus the inner parenthesis to wrap the type passed to the macro BOOST_IDENTITY_TYPE((...)).

This macro works on any C++03 compiler (because it does not use variadic macros). [1]

This macro must be prefixed by typename when used within templates. For example, let's program a macro that declares a function parameter named argn with the specified type (see also template.cpp):

#define ARG(type, n) type arg ## n

template<typename T>
void f( // Prefix macro with `typename` in templates.
    ARG(typename BOOST_IDENTITY_TYPE((std::map<int, T>)), 1)
) {
    std::cout << arg1[0] << std::endl;
}

std::map<int, char> a;
a[0] = 'a';

f<char>(a); // OK...
// f(a);    // ... but error.

However, note that the template parameter char must be manually specified when invoking the function f<char>(a). In fact, when the BOOST_IDENTITY_TYPE macro is used to wrap a function template parameter, the template parameter can no longer be automatically deduced by the compiler form the function call as in f(a). [2] (This limitation does not apply to class templates because class template parameters must always be explicitly specified.) In other words, without using the BOOST_IDENTITY_TYPE macro, C++ would normally be able to automatically deduce the function template parameter as shown below:

template<typename T>
void g(
    std::map<int, T> arg1
) {
    std::cout << arg1[0] << std::endl;
}

g<char>(a); // OK...
g(a);       // ... and also OK.

On some compilers (e.g., GCC), using this macro on abstract types (i.e., classes with one or more pure virtual functions) generates a compiler error. This can be worked around by manipulating the type adding and removing a reference to it.

Let's program a macro that performs a static assertion on a Template Meta-Programming (TMP) meta-function (similarly to Boost.MPL BOOST_MPL_ASSERT). The BOOST_IDENTITY_TYPE macro can be used to pass a meta-function with multiple template parameters to the assert macro (so to handle the commas separating the template parameters). In this case, if the meta-function is an abstract type, it needs to be manipulated adding and removing a reference to it (see also abstract.cpp):

#define TMP_ASSERT(metafunction) \
    BOOST_STATIC_ASSERT(metafunction::value)

template<typename T, bool b>
struct abstract {
    static const bool value = b;
    virtual void f(T const& x) = 0;     // Pure virtual function.
};

TMP_ASSERT(
    boost::remove_reference<            // Add and remove
        BOOST_IDENTITY_TYPE((           // reference for
            boost::add_reference<       // abstract type.
                abstract<int, true>
            >::type
        ))
    >::type
);

The authors originally developed and tested the library on:

  1. GNU Compiler Collection (GCC) C++ 4.5.3 (with and without C++11 features enabled -std=c++0x) on Cygwin.
  2. Miscrosoft Visual C++ (MSVC) 8.0 on Windows 7.

See the library regressions test results for detailed information on supported compilers and platforms.

The BOOST_IDENTITY_TYPE macro can be used either when calling a user-defined macro (as shown by the examples so far), or internally in the definition of a user-defined macro (as shown below). When BOOST_IDENTITY_TYPE is used in the user macro definition, the call of the user macro will only have to specify the extra parenthesis (see also paren.cpp):

#define TMP_ASSERT_PAREN(parenthesized_metafunction) \
    /* use `BOOST_IDENTITY_TYPE` in macro definition instead of invocation */ \
    BOOST_STATIC_ASSERT(BOOST_IDENTITY_TYPE(parenthesized_metafunction)::value)

#define TMP_ASSERT(metafunction) \
    BOOST_STATIC_ASSERT(metafunction::value)

// Specify only extra parenthesis `((...))`.
TMP_ASSERT_PAREN((boost::is_const<std::map<int, char> const>));

// Specify both the extra parenthesis `((...))` and `BOOST_IDENTITY_TYPE` macro.
TMP_ASSERT(BOOST_IDENTITY_TYPE((boost::is_const<std::map<int, char> const>)));

However, note that the user will always have to specify the extra parenthesis even when the macro parameters contain no comma:

TMP_ASSERT_PAREN((boost::is_const<int const>)); // Always extra `((...))`.

TMP_ASSERT(boost::is_const<int const>); // No extra `((...))` and no macro.

In some cases, using BOOST_IDENTITY_TYPE within the user macro definition might provide the best syntax for the user. For example, this is the case for BOOST_MPL_ASSERT because the majority of template meta-programming expressions contain unwrapped commas so it is less confusing for the user to always specify the extra parenthesis ((...)) instead of using BOOST_IDENTITY_TYPE:

BOOST_MPL_ASSERT(( // Natural syntax.
    boost::mpl::and_<
          boost::is_const<T>
        , boost::is_reference<T>
    >
));

However, in other situations it might be preferable to not require the extra parenthesis in the common cases and handle commas as special cases using BOOST_IDENTITY_TYPE. For example, this is the case for BOOST_LOCAL_FUNCTION for which always requiring the extra parenthesis ((...)) around the types would lead to an unnatural syntax for the local function signature:

int BOOST_LOCAL_FUNCTION( ((int&)) x, ((int&)) y ) { // Unnatural syntax.
    return x + y;
} BOOST_LOCAL_FUNCTION_NAME(add)

Instead requiring the user to specify BOOST_IDENTITY_TYPE only when needed allows for the more natural syntax BOOST_LOCAL_FUNCTION(int& x, int& y) in the common cases when the parameter types contain no comma.

The implementation of this library macro is equivalent to the following: [3]

#include <boost/type_traits/function_traits.hpp>

#define BOOST_IDENTITY_TYPE(parenthesized_type) \
    boost::function_traits<void parenthesized_type>::arg1_type

Essentially, the type is wrapped between round parenthesis (std::map<int, char>) so it can be passed as a single macro parameter even if it contains commas. Then the parenthesized type is transformed into the type of a function returning void and with the specified type as the type of the first and only argument void (std::map<int, char>). Finally, the type of the first argument arg1_type is extracted at compile-time using the function_traits meta-function therefore obtaining the original type from the parenthesized type (effectively stripping the extra parenthesis from around the specified type).

Reference

Wrap type expressions with round parenthesis so they can be passed to macros even if they contain commas.


BOOST_IDENTITY_TYPE(parenthesized_type)

Macro BOOST_IDENTITY_TYPE

BOOST_IDENTITY_TYPE — This macro allows to wrap the specified type expression within extra round parenthesis so the type can be passed as a single macro parameter even if it contains commas (not already wrapped within round parenthesis).

Synopsis

// In header: <boost/utility/identity_type.hpp>

BOOST_IDENTITY_TYPE(parenthesized_type)

Description

Parameters:

parenthesized_typeThe type expression to be passed as macro parameter wrapped by a single set of round parenthesis (...). This type expression can contain an arbitrary number of commas.

This macro works on any C++03 compiler (it does not require variadic macros).

This macro must be prefixed by typename when used within templates. However, the compiler will not be able to automatically determine function template parameters when they are wrapped with this macro (these parameters need to be explicitly specified when calling the function template).

On some compilers (like GCC), using this macro on an abstract types requires to add and remove a reference to the type.



[1] Using variadic macros, it would be possible to require a single set of extra parenthesis BOOST_IDENTITY_TYPE(type) instead of two BOOST_IDENTITY_TYPE((type)) but variadic macros are not part of C++03 (even if nowadays they are supported by most modern compilers and they are also part of C++11).

[2] This is because the implementation of BOOST_IDENTITY_TYPE wraps the specified type within a meta-function.

[3] There is absolutely no guarantee that the macro is actually implemented using the code listed in this documentation. This code is for explanatory purposes only.