From 5825b6c3299ed9079438976f0245ed70933434a6 Mon Sep 17 00:00:00 2001
From: Lorenzo Caminiti
- Consider the following macro which declares a variable named var
n with the specified
- type (see also var_error.cpp
):
+ Consider the following macro which declares a variable named var
n
+ with the specified type
(see also
+ var_error.cpp
):
#define VAR(type, n) type var ## n -VAR( int, 1 ); // OK. -VAR( std::map<int, char>, 2 ); // Error. +VAR(int, 1); // OK. +VAR(std::map<int, char>, 2); // Error.
The first macro invocation works correctly declaring a variable named var1
of type int
.
@@ -45,7 +46,7 @@
the type expression with the commas outside the macro (see also var.cpp
):
typedef std::map<int, char> map_type; -VAR( map_type, 3 ); // OK. +VAR(map_type, 3); // OK.
When this is not possible or desired (e.g., see the function template f
in the section below), the library header
@@ -56,7 +57,7 @@
#include <boost/utility/identity_type.hpp> -VAR( BOOST_IDENTITY_TYPE((std::map<int, char>)), 4 ); // OK. +VAR(BOOST_IDENTITY_TYPE((std::map<int, char>)), 4); // OK.
This macro expands to an expression that evaluates (at compile-time) to the @@ -71,14 +72,15 @@
This macro must be prefixed by typename
when used within templates. For example, let's program a macro that declares
- a function parameter named arg
n
- with the specified type (see also template.cpp
):
+ a function parameter named arg
n
+ with the specified type
(see also
+ template.cpp
):
#define ARG(type, n) type arg ## n template<typename T> void f( // Prefix macro with `typename` in templates. - ARG( typename BOOST_IDENTITY_TYPE((std::map<int, T>)), 1 ) + ARG(typename BOOST_IDENTITY_TYPE((std::map<int, T>)), 1) ) { std::cout << arg1[0] << std::endl; } @@ -87,20 +89,20 @@std::map<int, char> a; a[0] = 'a'; -f<char>(a); // OK. -// f(a); // But error. +f<char>(a); // OK... +// f(a); // ... but error.
- However, note that the template parameter type
char
- must be explicitly specified when invoking the functionf<char>(a)
. In fact, + However, note that the template parameterchar
+ must be manually specified when invoking the functionf<char>(a)
. In fact, when theBOOST_IDENTITY_TYPE
macro is used to wrap a function template parameter, the template parameter - can no longer be implicitly determined by the compiler form the function call - as inf(a)
. (This - limitation does not apply to class templates because class template parameters - must always be explicitly specified.) In other words, without using theBOOST_IDENTITY_TYPE
macro, C++ would - normally be able to implicitly deduce the function template parameter as shown - below: + can no longer be automatically deduced by the compiler form the function call + as inf(a)
. [2] (This limitation does not apply to class templates because class + template parameters must always be explicitly specified.) In other words, without + using theBOOST_IDENTITY_TYPE
+ macro, C++ would normally be able to automatically deduce the function template + parameter as shown below:
template<typename T> void g( @@ -110,14 +112,14 @@ }
-
g<char>(a); // OK. -g(a); // Also OK. +g<char>(a); // OK... +g(a); // ... and also OK.
- On some compilers (e.g., GCC), using this macro on abstract types (i.e., a - class with one or more pure virtual functions) generates a compiler error. - This can be worked around by manipulating the type adding and removing a reference - to it. + On some compilers (e.g., GCC), using this macro on abstract types (i.e., classes + with one or more pure virtual functions) generates a compiler error. This can + be worked around by manipulating the type adding and removing a reference to + it.
Let's program a macro that performs a static assertion on a Template
Meta-Programming (TMP) meta-function (similarly to Boost.MPL BOOST_MPL_ASSERT
). The BOOST_IDENTITY_TYPE
macro can be used
@@ -132,7 +134,7 @@
template<typename T, bool b>
struct abstract {
static const bool value = b;
- virtual void f(T const& x) = 0;
+ virtual void f(T const& x) = 0; // Pure virtual function.
};
TMP_ASSERT(
@@ -147,29 +149,32 @@
The BOOST_IDENTITY_TYPE
macro
- can be used either in the call of the user-defined macro (as shown by the examples
- so far), or internally to the definition of the user macro. When BOOST_IDENTITY_TYPE
is used internally,
- the call of the user macro will only have to specify the extra parenthesis
- (see also tmp_assert.cpp
):
+ can be used either when calling a user-defined macro (as shown by the examples
+ so far), or internally in the definition of a user-defined macro (as shown
+ below). When BOOST_IDENTITY_TYPE
+ is used in the user macro definition, the call of the user macro will only
+ have to specify the extra parenthesis (see also tmp_assert.cpp
):
#define TMP_ASSERT_PAREN(parenthesized_metafunction) \ /* use `BOOST_IDENTITY_TYPE` in macro definition instead of invocation */ \ BOOST_STATIC_ASSERT(BOOST_IDENTITY_TYPE(parenthesized_metafunction)::value) -TMP_ASSERT_PAREN(( boost::is_const<std::map<int, char> const> )); -TMP_ASSERT( BOOST_IDENTITY_TYPE((boost::is_const<std::map<int, char> const>)) ); +// Specify only extra parenthesis `((...))`. +TMP_ASSERT_PAREN((boost::is_const<std::map<int, char> const>)); +// Specify both the extra parenthesis `((...))` and `BOOST_IDENTITY_TYPE` macro. +TMP_ASSERT(BOOST_IDENTITY_TYPE((boost::is_const<std::map<int, char> const>)));
However, note that the user will always have to specify the extra parenthesis even when the macro parameters contain no comma:
-
TMP_ASSERT_PAREN(( boost::is_const<int const> )); // Always extra `()`. -TMP_ASSERT( boost::is_const<int const> ); // No extra `()` and no macro. +TMP_ASSERT_PAREN((boost::is_const<int const>)); // Always extra `((...))`. +TMP_ASSERT(boost::is_const<int const>); // No extra `((...))` and no macro.
In some cases, using
BOOST_IDENTITY_TYPE
- internally might provide the best syntax for the user. For example, this is - the case forBOOST_MPL_ASSERT
+ within the user macro definition might provide the best syntax for the user. + For example, this is the case forBOOST_MPL_ASSERT
because the majority of template meta-programming expressions contain unwrapped commas so it is less confusing for the user to always specify the extra parenthesis((...))
instead of usingBOOST_IDENTITY_TYPE
: @@ -181,22 +186,21 @@ ));
However, in other situations it might be preferable to not require the extra
- parenthesis in common cases and handle commas as special cases using the BOOST_IDENTITY_TYPE
. For example, this
- is the case for BOOST_LOCAL_FUNCTION
- for which always requiring the extra parenthesis ((...))
- around the types would lead to an unnatural syntax for the local function parameter
- types:
+ parenthesis in the common cases and handle commas as special cases using BOOST_IDENTITY_TYPE
. For example, this
+ is the case for BOOST_LOCAL_FUNCTION
for which always
+ requiring the extra parenthesis ((...))
+ around the types would lead to an unnatural syntax for the local function signature:
int BOOST_LOCAL_FUNCTION( ((int&)) x, ((int&)) y ) { // Unnatural syntax. return x + y; } BOOST_LOCAL_FUNCTION_NAME(add)
Instead requiring the user to specify BOOST_IDENTITY_TYPE
- when needed allows for the more natural syntax BOOST_LOCAL_FUNCTION(int&
+ only when needed allows for the more natural syntax
BOOST_LOCAL_FUNCTION(int&
x, int& y)
in the common cases when the parameter types
contain no comma.
- The implementation of this library macro is equivalent to the following: [2] + The implementation of this library macro is equivalent to the following: [3]
#include <boost/type_traits/function_traits.hpp> #define BOOST_IDENTITY_TYPE(parenthesized_type) \ @@ -204,24 +208,29 @@
Essentially, the type is wrapped between round parenthesis (std::map<int,
char>)
- so it can be passed as a macro parameter even if it contain commas. Then the
- parenthesized type is transformed into the type of a function returning void
and with the specified type as the type
- of the first and only argument void
+ so it can be passed as a single macro parameter even if it contains commas.
+ Then the parenthesized type is transformed into the type of a function returning
+
void
and with the specified type
+ as the type of the first and only argument void
(std::map<int, char>)
. Finally, the type of the first argument
- arg1_type
is extracted therefore
- obtaining the original type from the parenthesized type (effectively stripping
- the parenthesis from around the type).
+ arg1_type
is extracted at compile-time
+ using the function_traits
meta-function
+ therefore obtaining the original type from the parenthesized type (effectively
+ stripping the extra parenthesis from around the specified type).
Wrap type expressions with round parenthesis so they can be passed to macros even if they contain commas.
BOOST_IDENTITY_TYPE(parenthesized_type)
BOOST_IDENTITY_TYPE — This macro allows to wrap the specified type expression within extra round parenthesis so the type can be passed as a single macro parameter even if it contains commas (not already wrapped within round parenthesis).
// In header: <boost/utility/identity_type.hpp>
-BOOST_IDENTITY_TYPE(parenthesized_type)
Parameters:
parenthesized_type | The type expression to be passed as macro parameter wrapped by a single set of round parenthesis (...) . This type expression can contain an arbitrary number of commas. |
+BOOST_IDENTITY_TYPE(parenthesized_type)
Parameters:
parenthesized_type | The type expression to be passed as macro parameter wrapped by a single set of round parenthesis (...) . This type expression can contain an arbitrary number of commas. |
This macro works on any C++03 compiler (it does not require variadic macros).
This macro must be prefixed by typename
when used within templates. However, the compiler will not be able to automatically determine function template parameters when they are wrapped with this macro (these parameters need to be explicitly specified when calling the function template).
On some compilers (like GCC), using this macro on an abstract types requires to add and remove a reference to the type.
[1]
- Using variadic macros, it would be possible to use a single set of parenthesis
- BOOST_IDENTITY_TYPE(
type)
instead of two BOOST_IDENTITY_TYPE((
type))
- but variadic macros are not part of C++03 (even if nowadays they are supported
- by most modern compilers and they are also part of C++11).
-
[2]
+ Using variadic macros, it would be possible to require a single set of extra
+ parenthesis BOOST_IDENTITY_TYPE(
type
)
instead of two BOOST_IDENTITY_TYPE((
type
))
but variadic macros are not part of C++03
+ (even if nowadays they are supported by most modern compilers and they are
+ also part of C++11).
+
[2]
+ This is because the implementation of BOOST_IDENTITY_TYPE
+ wraps the specified type within a meta-function.
+
[3]
There is absolutely no guarantee that the macro is actually implemented using
the code listed in this documentation. This code is for explanatory purposes
only.
diff --git a/identity_type/doc/identity_type.qbk b/identity_type/doc/identity_type.qbk
index 2723d33..3ef0b12 100644
--- a/identity_type/doc/identity_type.qbk
+++ b/identity_type/doc/identity_type.qbk
@@ -28,7 +28,7 @@ This library allows to wrap type expressions within round parenthesis so they ca
[section Motivation]
-Consider the following macro which declares a variable named `var`/n/ with the specified /type/ (see also [@../../test/var_error.cpp =var_error.cpp=]):
+Consider the following macro which declares a variable named `var`[^['n]] with the specified [^['type]] (see also [@../../test/var_error.cpp =var_error.cpp=]):
[var_error]
@@ -68,7 +68,7 @@ In fact, a total of two sets of round parenthesis must be used: The parenthesis
This macro works on any [@http://www.open-std.org/JTC1/SC22/WG21/docs/standards C++03] compiler (because it does not use [@http://en.wikipedia.org/wiki/Variadic_macro variadic macros]).
[footnote
-Using variadic macros, it would be possible to use a single set of parenthesis `BOOST_IDENTITY_TYPE(`/type/`)` instead of two `BOOST_IDENTITY_TYPE((`/type/`))` but variadic macros are not part of C++03 (even if nowadays they are supported by most modern compilers and they are also part of C++11).
+Using variadic macros, it would be possible to require a single set of extra parenthesis `BOOST_IDENTITY_TYPE(`[^['type]]`)` instead of two `BOOST_IDENTITY_TYPE((`[^['type]]`))` but variadic macros are not part of C++03 (even if nowadays they are supported by most modern compilers and they are also part of C++11).
]
[endsect]
@@ -76,15 +76,18 @@ Using variadic macros, it would be possible to use a single set of parenthesis `
[section Templates]
This macro must be prefixed by `typename` when used within templates.
-For example, let's program a macro that declares a function parameter named `arg`/n/ with the specified /type/ (see also [@../../test/template.cpp =template.cpp=]):
+For example, let's program a macro that declares a function parameter named `arg`[^['n]] with the specified [^['type]] (see also [@../../test/template.cpp =template.cpp=]):
[template_f_decl]
[template_f_call]
-However, note that the template parameter type `char` must be explicitly specified when invoking the function `f