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refactor: reference::operator() return type constraints improved

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Mateusz Pusz
2022-12-22 21:28:49 +01:00
parent e61bfafd29
commit 0caf998df1
1 changed files with 1 additions and 1 deletions
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src/core/include/units/reference.h
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@@ -53,7 +53,7 @@ struct reference {
template<RepresentationOf<Q.character> Rep> template<RepresentationOf<Q.character> Rep>
// TODO can we somehow return an explicit quantity type here? // TODO can we somehow return an explicit quantity type here?
[[nodiscard]] constexpr Quantity auto operator()(Rep&& value) const [[nodiscard]] constexpr std::same_as<quantity<reference{}, Rep>> auto operator()(Rep&& value) const
{ {
return quantity<reference{}, Rep>(std::forward<Rep>(value)); return quantity<reference{}, Rep>(std::forward<Rep>(value));
} }