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Fix that raw string literals that close on same line were not terminated

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With the built-in model, which affects basic highlighting.

Task-number: QTCREATORBUG-17720
Change-Id: I7369d7288d9c2c8e5ef36fc27549121014527e58
Reviewed-by: Nikolai Kosjar <nikolai.kosjar@qt.io>
This commit is contained in:
Eike Ziller
2017-05-18 12:46:19 +02:00
parent a37c8add58
commit 4e35cc2ea8
2 changed files with 19 additions and 1 deletions
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4
src/libs/3rdparty/cplusplus/Lexer.cpp vendored
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@@ -748,6 +748,7 @@ void Lexer::scanRawStringLiteral(Token *tok, unsigned char hint)
int delimLength = -1;
const char *closingDelimCandidate = 0;
bool closed = false;
while (_yychar) {
if (_yychar == '(' && delimLength == -1) {
delimLength = _currentChar - yytext;
@@ -769,6 +770,7 @@ void Lexer::scanRawStringLiteral(Token *tok, unsigned char hint)
if (_yychar == '"') {
if (delimLength == _currentChar - closingDelimCandidate) {
// Got a matching closing delimiter.
closed = true;
break;
}
}
@@ -802,7 +804,7 @@ void Lexer::scanRawStringLiteral(Token *tok, unsigned char hint)
else
tok->f.kind = T_RAW_STRING_LITERAL;
if (!_yychar)
if (!closed)
s._tokenKind = tok->f.kind;
}