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Qml Debugging: Default option for Qt Quick application

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Qt Quick applications should have Qml Debugging enabled
by default.

Task-number: QTCREATORBUG-8208
Change-Id: I794249567b15071098f0ac8ba5f2a8e5f2be4ffb
Reviewed-by: hjk <hjk121@nokiamail.com>
This commit is contained in:
Aurindam Jana
2012-11-21 16:18:53 +01:00
committed by hjk
parent 776f078d53
commit 5cf11e2bbd
9 changed files with 33 additions and 28 deletions
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16
src/plugins/projectexplorer/runconfiguration.cpp
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@@ -157,23 +157,11 @@ bool DebuggerRunConfigurationAspect::useCppDebugger() const
return m_useCppDebugger;
}
static bool isQtQuickAppProject(Project *project)
{
const QString projectDirectory = project->projectDirectory();
// Qt Quick 1 wizard generated file
const QString qq1FilePath = projectDirectory
+ QLatin1String("/qmlapplicationviewer/qmlapplicationviewer.pri");
// Qt Quick 2 wizard generated file
const QString qq2FilePath = projectDirectory
+ QLatin1String("/qtquick2applicationviewer/qtquick2applicationviewer.pri");
const QStringList projectFiles = project->files(Project::ExcludeGeneratedFiles);
return projectFiles.contains(qq1FilePath) || projectFiles.contains(qq2FilePath);
}
bool DebuggerRunConfigurationAspect::useQmlDebugger() const
{
if (m_useQmlDebugger == DebuggerRunConfigurationAspect::AutoEnableQmlDebugger)
return isQtQuickAppProject(m_runConfiguration->target()->project());
return m_runConfiguration->target()->project()->projectLanguages().contains(
ProjectExplorer::Constants::LANG_QMLJS);
return m_useQmlDebugger == DebuggerRunConfigurationAspect::EnableQmlDebugger;
}