forked from qt-creator/qt-creator
Qml Debugging: Default option for Qt Quick application
Qt Quick applications should have Qml Debugging enabled by default. Task-number: QTCREATORBUG-8208 Change-Id: I794249567b15071098f0ac8ba5f2a8e5f2be4ffb Reviewed-by: hjk <hjk121@nokiamail.com>
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@@ -348,7 +348,7 @@ Qt4Project::Qt4Project(Qt4Manager *manager, const QString& fileName) :
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m_activeTarget(0)
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{
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setProjectContext(Core::Context(Qt4ProjectManager::Constants::PROJECT_ID));
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setProjectLanguage(Core::Context(ProjectExplorer::Constants::LANG_CXX));
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setProjectLanguages(Core::Context(ProjectExplorer::Constants::LANG_CXX));
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m_asyncUpdateTimer.setSingleShot(true);
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m_asyncUpdateTimer.setInterval(3000);
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@@ -599,10 +599,27 @@ void Qt4Project::updateQmlJSCodeModel()
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QList<Qt4ProFileNode *> proFiles = findQt4ProFiles(rootProjectNode());
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projectInfo.importPaths.clear();
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bool hasQmlLib = false;
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foreach (Qt4ProFileNode *node, proFiles) {
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projectInfo.importPaths.append(node->variableValue(QmlImportPathVar));
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if (!hasQmlLib) {
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QStringList qtLibs = node->variableValue(QtVar);
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hasQmlLib = qtLibs.contains(QLatin1String("declarative")) ||
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qtLibs.contains(QLatin1String("qml")) ||
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qtLibs.contains(QLatin1String("quick"));
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}
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}
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// If the project directory has a pro/pri file that includes a qml or quick or declarative
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// library then chances of the project being a QML project is quite high.
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// This assumption fails when there are no QDeclarativeEngine/QDeclarativeView (QtQuick 1)
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// or QQmlEngine/QQuickView (QtQuick 2) instances.
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Core::Context pl(ProjectExplorer::Constants::LANG_CXX);
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if (projectInfo.sourceFiles.count() && hasQmlLib)
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pl.add(ProjectExplorer::Constants::LANG_QMLJS);
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setProjectLanguages(pl);
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bool preferDebugDump = false;
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projectInfo.tryQmlDump = false;
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