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debugger: provide an entry saying <no information> if an object has no

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children (or no debug information available)
This commit is contained in:
hjk
2009-04-09 11:35:58 +02:00
parent cb75dd05ea
commit 971c1999d2
1 changed files with 15 additions and 1 deletions
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16
src/plugins/debugger/gdbengine.cpp
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@@ -3955,9 +3955,23 @@ void GdbEngine::handleVarListChildren(const GdbResultRecord &record,
foreach (const GdbMi &child, children.children())
handleVarListChildrenHelper(child, data);
if (!isAccessSpecifier(data.variable.split('.').takeLast())) {
if (children.children().isEmpty()) {
// happens e.g. if no debug information is present or
// if the class really has no children
WatchData data1;
data1.iname = data.iname + ".child";
data1.value = tr("<no information>");
data1.childCount = 0;
data1.setAllUnneeded();
insertData(data1);
data.setAllUnneeded();
insertData(data);
} else if (!isAccessSpecifier(data.variable.split('.').takeLast())) {
data.setChildrenUnneeded();
insertData(data);
} else {
// this skips the spurious "public", "private" etc levels
// gdb produces
}
} else if (record.resultClass == GdbResultError) {
data.setError(record.data.findChild("msg").data());