C++: name of function of class problem

It fixes:
* highlighing
* find usage
* follow symbol

when function of class has the same name as:
* local variable
* template parameter
* other struct/union/class/enum
* function argument

in function scope.

Task-number: QTCREATORBUG-8902
Change-Id: Iddc0f764af689babb40d39460d174bac7b919b31
Reviewed-by: Orgad Shaneh <orgads@gmail.com>
Reviewed-by: Sergey Shambir <sergey.shambir.auto@gmail.com>
Reviewed-by: Erik Verbruggen <erik.verbruggen@digia.com>

src/plugins/cpptools/cppchecksymbols.cpp

@@ -1240,6 +1240,7 @@ bool CheckSymbols::maybeAddFunction(const QList<LookupItem> &candidates, NameAST
 {
     unsigned startToken = ast->firstToken();
     bool isDestructor = false;
+    bool isConstructor = false;
     if (DestructorNameAST *dtor = ast->asDestructorName()) {
         isDestructor = true;
         if (dtor->unqualified_name)
@@ -1264,6 +1265,8 @@ bool CheckSymbols::maybeAddFunction(const QList<LookupItem> &candidates, NameAST
         if (isDestructor != c->name()->isDestructorNameId())
             continue;
 
+        isConstructor = isConstructorDeclaration(c);
+
         Function *funTy = c->type()->asFunctionType();
         if (! funTy) {
             //Try to find a template function
@@ -1296,7 +1299,9 @@ bool CheckSymbols::maybeAddFunction(const QList<LookupItem> &candidates, NameAST
     }
 
     if (matchType != Match_None) {
+        // decide how constructor and destructor should be highlighted
         if (highlightCtorDtorAsType
+                && (isConstructor || isDestructor)
                 && maybeType(ast->name)
                 && kind == SemanticInfo::FunctionUse) {
             return false;
@@ -1399,3 +1404,12 @@ void CheckSymbols::flush()
     _usages.clear();
     _usages.reserve(cap);
 }
+
+bool CheckSymbols::isConstructorDeclaration(Symbol *declaration)
+{
+    Class *clazz = declaration->enclosingClass();
+    if (clazz && clazz->name())
+        return declaration->name()->isEqualTo(clazz->name());
+
+    return false;
+}