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C++: fix tooltip for constantValue of enumeratorDeclaration

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E.g.:
enum E { x = 1 + 2 + 1 };

constantValue for enumeratorDeclaration currently is equal: '1+2+1'
(spaces between are removed).
Fixed version produces "1 + 2 + 1".

Change-Id: I38f7703bd5c856c28aadeecd7f7923aa4a7da422
Reviewed-by: Nikolai Kosjar <nikolai.kosjar@digia.com>
This commit is contained in:
Przemyslaw Gorszkowski
2013-07-17 13:21:12 +02:00
committed by Nikolai Kosjar
parent fe39e8e9c3
commit f068223133
2 changed files with 4 additions and 6 deletions
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7
src/libs/3rdparty/cplusplus/Bind.cpp vendored
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@@ -476,7 +476,7 @@ void Bind::enumerator(EnumeratorAST *ast, Enum *symbol)
e->setType(control()->integerType(IntegerType::Int)); // ### introduce IntegerType::Enumerator
if (ExpressionAST *expr = ast->expression)
e->setConstantValue(asStringLiteral(expr->firstToken(), expr->lastToken(), false));
e->setConstantValue(asStringLiteral(expr->firstToken(), expr->lastToken()));
symbol->addMember(e);
}
@@ -1137,13 +1137,12 @@ FullySpecifiedType Bind::trailingReturnType(TrailingReturnTypeAST *ast, const Fu
return type;
}
const StringLiteral *Bind::asStringLiteral(unsigned firstToken, unsigned lastToken,
bool addWhitespace)
const StringLiteral *Bind::asStringLiteral(unsigned firstToken, unsigned lastToken)
{
std::string buffer;
for (unsigned index = firstToken; index != lastToken; ++index) {
const Token &tk = tokenAt(index);
if (addWhitespace && (tk.whitespace() || tk.newline()))
if (index != firstToken && (tk.whitespace() || tk.newline()))
buffer += ' ';
buffer += tk.spell();
}