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C++: Fix code compl. for instantiation of template specialization

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It works for full specialization. Instantiate of the partial
specialization has to be implemented(finding appropriate partial
specialization-on going)

Added unit test.

Change-Id: I8ef5ea963e7c665e0d67d390b3a833486773dab0
Reviewed-by: Erik Verbruggen <erik.verbruggen@digia.com>
This commit is contained in:
Przemyslaw Gorszkowski
2013-01-12 22:05:41 +01:00
parent 0135609973
commit ffba28d26a
13 changed files with 149 additions and 23 deletions
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8
src/libs/3rdparty/cplusplus/Templates.cpp vendored
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@@ -414,9 +414,10 @@ void CloneName::visit(const TemplateNameId *name)
for (unsigned i = 0; i < args.size(); ++i)
args[i] = _clone->type(name->templateArgumentAt(i), _subst);
if (args.empty())
_name = _control->templateNameId(_clone->identifier(name->identifier()));
_name = _control->templateNameId(_clone->identifier(name->identifier()), name->isSpecialization());
else
_name = _control->templateNameId(_clone->identifier(name->identifier()), &args[0], args.size());
_name = _control->templateNameId(_clone->identifier(name->identifier()), name->isSpecialization(),
&args[0], args.size());
}
void CloneName::visit(const DestructorNameId *name)
@@ -528,7 +529,8 @@ FullySpecifiedType Subst::apply(const Name *name) const
const NamedType *name = apply(q->base())->asNamedType();
const NamedType *unqualified = apply(q->name())->asNamedType();
if (name && name->name()->identifier() != 0 && unqualified)
return control()->namedType(control()->qualifiedNameId(name->name()->identifier(), unqualified->name()));
return control()->namedType(control()->qualifiedNameId(name->name()->identifier(),
unqualified->name()));
}
}