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Simplify has_formatter

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This commit is contained in:
Victor Zverovich
2024-09-16 20:15:54 -07:00
parent 3374a95b50
commit 503dff93ec
1 changed files with 3 additions and 5 deletions
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8
include/fmt/base.h
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@ -1107,11 +1107,9 @@ struct use_formatter
!has_to_string_view<T>::value && !is_named_arg<T>::value && !has_to_string_view<T>::value && !is_named_arg<T>::value &&
!use_format_as<T>::value> {}; !use_format_as<T>::value> {};
template <typename Char, typename T> template <typename Char, typename T, typename U = remove_const_t<T>>
auto has_formatter_impl(T* p) auto has_formatter_impl(T* p, buffered_context<Char>* ctx = nullptr)
-> decltype(formatter<remove_const_t<T>, Char>().format( -> decltype(formatter<U, Char>().format(*p, *ctx), std::true_type());
*p, std::declval<buffered_context<Char>&>()),
std::true_type());
template <typename Char> auto has_formatter_impl(...) -> std::false_type; template <typename Char> auto has_formatter_impl(...) -> std::false_type;
// T can be const-qualified to check if it is const-formattable. // T can be const-qualified to check if it is const-formattable.
template <typename T, typename Char> constexpr auto has_formatter() -> bool { template <typename T, typename Char> constexpr auto has_formatter() -> bool {