Updated FAQ (markdown)

FAQ.md

@@ -96,4 +96,42 @@ This will never be a part of the library.
 
 See issues [#72](https://github.com/bblanchon/ArduinoJson/issues/72), [#115](https://github.com/bblanchon/ArduinoJson/issues/115), [#141](https://github.com/bblanchon/ArduinoJson/issues/141)
 
-See [ArduinoJson: Avoiding pitfalls](https://github.com/bblanchon/ArduinoJson/wiki/Avoiding-pitfalls#4-dont-reuse-the-same-jsonbuffer)
+See [ArduinoJson: Avoiding pitfalls](https://github.com/bblanchon/ArduinoJson/wiki/Avoiding-pitfalls#4-dont-reuse-the-same-jsonbuffer)
+
+### What's the best way to use the library?
+
+Here is the canonical example for serializing and deserializing with ArduinoJson.
+
+By following this example, you are making the best usage of your memory and you maintain a good software design.
+
+```c++
+struct SensorData {
+   const char* name;
+   int time;
+   float value;
+};
+
+bool deserialize(SensorData& data, const char* json)
+{
+    StaticJsonBuffer<200> jsonBuffer;
+    JsonObject& root = jsonBuffer.parseObject(json)
+    data.name = json["name"];
+    data.time = json["time"];
+    data.value = json["value"];
+    return root.success();
+}
+
+void serialize(const SensorData& data, char* json, size_t maxSize)
+{
+    StaticJsonBuffer<200> jsonBuffer;
+    JsonObject& root = jsonBuffer.createObject()
+    root["name"] = data.name;
+    root["time"] = data.time;
+    root["value"] = data.value;
+    root.printTo(json, maxSize);
+}
+```
+
+As you can see the `StaticJsonBuffer` is kept in memory as short as possible, so that the remain of your program is unaffected by the JSON serialization.
+
+Also you can see that neither `JsonArray` nor `JsonObject` leak out of the serialization code. This maintain a good isolation and reduce the coupling with the library.