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worked around VS2015 issue
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@ -138,12 +138,27 @@ BOOST_UNORDERED_HAS_CONST_REFERENCE_ARG_MEMFUN(const volatile&&)
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/* Detects if f(x) takes x as a const reference. From an implementation
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* technique by Kenneth Gorking.
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* Requires: F is invocable with an Arg&.
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* takes_arg_as_const_reference implemented with an auxiliary
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* takes_arg_as_const_reference0 base because VS2015 erroneously matches
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* &F::operator() for templated call operators.
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*/
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template<typename F,typename /*Arg*/,typename=void>
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struct takes_arg_as_const_reference:
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struct takes_arg_as_const_reference0:
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has_const_reference_arg<remove_noexcept_t<F>>{};
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template<typename F,typename Arg>
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struct takes_arg_as_const_reference0<
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F,Arg,
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boost::void_t<decltype(&F::operator())>
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>:
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takes_arg_as_const_reference0<
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decltype(&F::operator()),Arg
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>{};
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template<typename F,typename Arg,typename=void>
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struct takes_arg_as_const_reference:takes_arg_as_const_reference0<F,Arg>{};
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#if BOOST_WORKAROUND(BOOST_MSVC,<1920)
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/* VS2017 and older issue a C3517 error when trying to obtain the type of
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* an instantiation of a function template with deduced return type if
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@ -173,16 +188,6 @@ takes_arg_as_const_reference<
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>{};
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#endif
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template<typename F,typename Arg>
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struct takes_arg_as_const_reference<
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F,Arg,
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boost::void_t<decltype(&F::operator())>
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>:
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takes_arg_as_const_reference<
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decltype(&F::operator()),Arg
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>{};
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} /* namespace foa */
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} /* namespace detail */
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} /* namespace unordered */
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