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Stop using 'std::denorm_present' as on many compilers it isn't present itself.

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[SVN r27916]
This commit is contained in:
Daniel James
2005-04-01 22:49:19 +00:00
parent 0aff6fe1a8
commit 733ded8185
1 changed files with 5 additions and 2 deletions
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7
test/hash_float_test.cpp
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@@ -51,7 +51,9 @@ void float_tests(T* = 0)
// My hash fails this one, I guess it's not that bad.
BOOST_WARN(x1(infinity) != x1(minus_infinity));
if(std::numeric_limits<T>::has_denorm == denorm_present) {
// This should really be 'has_denorm == denorm_present' but some
// compilers don't have 'denorm_present'. See also a leter use.
if(std::numeric_limits<T>::has_denorm) {
BOOST_CHECK(x1(std::numeric_limits<T>::denorm_min()) != x1(infinity));
BOOST_CHECK(x1(std::numeric_limits<T>::denorm_min()) != x1(minus_infinity));
}
@@ -85,7 +87,8 @@ void float_tests(T* = 0)
BOOST_CHECK(x1(std::numeric_limits<T>::epsilon()) != x1((T) 0));
if(std::numeric_limits<T>::has_denorm == denorm_present) {
// As before.
if(std::numeric_limits<T>::has_denorm) {
BOOST_CHECK(x1(std::numeric_limits<T>::denorm_min()) != x1(zero));
}