forked from TartanLlama/optional
'optional<T&>::and_then(F&& f) &&' calls f with lvalue reference
This makes sense. The 'optional' is an rvalue, but its contained type remains an lvalue reference. I.e. int i = 3; optional<int&>{i}.and_then([](int& r){return optional<int&>{++r}); The optional r-value still refers to 'i', which is not an r-value.
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@ -237,9 +237,14 @@ TEST_CASE("Monadic operations", "[monadic]") {
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REQUIRE(!o18r);
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const tl::optional<int> o19 = tl::nullopt;
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auto o19r =
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std::move(o19).and_then([](int i) { return tl::make_optional(42); });
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auto o19r = std::move(o19).and_then([](int i) { return tl::make_optional(42); });
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REQUIRE(!o19r);
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int i = 3;
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tl::optional<int&> o20{i};
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std::move(o20).and_then([](int& r){return tl::optional<int&>{++r};});
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REQUIRE(o20);
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REQUIRE(i == 4);
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}
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SECTION("constexpr and_then") {
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@ -1702,11 +1702,11 @@ public:
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/// \group and_then
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/// \synopsis template <class F>\nconstexpr auto and_then(F &&f) &&;
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template <class F> TL_OPTIONAL_11_CONSTEXPR auto and_then(F &&f) && {
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using result = detail::invoke_result_t<F, T &&>;
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using result = detail::invoke_result_t<F, T &>;
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static_assert(detail::is_optional<result>::value,
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"F must return an optional");
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return has_value() ? detail::invoke(std::forward<F>(f), std::move(**this))
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return has_value() ? detail::invoke(std::forward<F>(f), **this)
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: result(nullopt);
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}
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@ -1725,11 +1725,11 @@ public:
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/// \group and_then
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/// \synopsis template <class F>\nconstexpr auto and_then(F &&f) const &&;
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template <class F> constexpr auto and_then(F &&f) const && {
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using result = detail::invoke_result_t<F, const T &&>;
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using result = detail::invoke_result_t<F, const T &>;
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static_assert(detail::is_optional<result>::value,
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"F must return an optional");
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return has_value() ? detail::invoke(std::forward<F>(f), std::move(**this))
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return has_value() ? detail::invoke(std::forward<F>(f), **this)
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: result(nullopt);
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}
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#endif
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