QmlJS: Fix lexer handling of escape sequences (again)

The lexer handled escape sequences already, but not fully
correct.
This effectively reverts 63db0f271f and fixes the wrong
offset.

Task-number: QTCREATORBUG-23830
Change-Id: I2cc1e9df5c0218cf9ee80998adce69bbc2eb4dab
Reviewed-by: Ulf Hermann <ulf.hermann@qt.io>
This commit is contained in:
Christian Stenger
2020-04-29 15:06:32 +02:00
parent 8806ae3bdf
commit 549b5719f6

View File

@@ -872,7 +872,6 @@ int Lexer::scanString(ScanStringMode mode)
{
QChar quote = (mode == TemplateContinuation) ? QChar(TemplateHead) : QChar(mode);
bool multilineStringLiteral = false;
bool escaped = false;
const QChar *startCode = _codePtr - 1;
// in case we just parsed a \r, we need to reset this flag to get things working
@@ -881,12 +880,6 @@ int Lexer::scanString(ScanStringMode mode)
if (_engine) {
while (_codePtr <= _endPtr) {
if (escaped) { // former char started an escape sequence
escaped = false;
_char = *_codePtr++;
++_currentColumnNumber;
continue;
}
if (isLineTerminator()) {
if ((quote == QLatin1Char('`') || qmlMode()))
break;
@@ -894,10 +887,7 @@ int Lexer::scanString(ScanStringMode mode)
_errorMessage = QCoreApplication::translate("QmlParser", "Stray newline in string literal");
return T_ERROR;
} else if (_char == QLatin1Char('\\')) {
if (mode != DoubleQuote && mode != SingleQuote)
break;
else // otherwise we need to handle an escape sequence
escaped = true;
break;
} else if (_char == '$' && quote == QLatin1Char('`')) {
break;
} else if (_char == quote) {
@@ -923,6 +913,7 @@ int Lexer::scanString(ScanStringMode mode)
// rewind by one char, so things gets scanned correctly
--_codePtr;
--_currentColumnNumber;
_validTokenText = true;
_tokenText = QString(startCode, _codePtr - startCode);